CN | IP address Subnetting Supernetting | Classless Inter Domain Routing (CIDR) |Ravindrababu Ravula

35 thoughts on “CN | IP address Subnetting Supernetting | Classless Inter Domain Routing (CIDR) |Ravindrababu Ravula”

• Layer wise chapter daal sakte h kya sir.

• Sir, I love this playlist. The efforts you have put into making all these videos are tremendous. I could not find some videos in this playlist. It is showing some videos in this playlist are hidden and unavailable.

• Is all the examples related to supernetting or CIDR

• Even in college semester this topic was not explained the way Ravinder sir has explained this topic. great explanation

• Great lessons but how can I view part 4 and part 5 of this series? I am a subscriber still I can't watch it as it seem to be private and hidden.

• Sir, please post the lecture 4 video also.. 🙏🙏

• Where is lecture 4?

• 127-63 = 64
  32-63 = 32
  how ????

• Mjaa aagya sir

• Thankyou Sir ❤️❤️ World needs teacher like you only !!❣️❣️

• Stupid me, I thought CN is tough😅

• at last found a excellent video tnx 🙂

• awesome

• An internet service provider (ISP) has following chunk of CIDR-based IP addresses available with it: 245.248.128.0/20 . The ISP want to give half of this chunk of addresses to organization A and a quarter to Organization B while retaining the remaining with itself. Which of the following is a valid allocation of addresses to A and B ? Sir Can you please explain how this question can be solved .

• How can any IP from the block could be used to derive another IPs of that block; at least the IP numbers which lies before the CIDR representation of an IP? How can 152.10.20.65/26 could derive 152.10.20.64 ?

• Please explain routing and other networking on switch level too i will look forward for your videos

• Awesome Sir i never used to get this networking going but you made it look so easy . Hatsoff sir .

• You are gift to students by God.😇

• Truly amazing lecture!! ♥️

• Thanks sir
  Thanks god

• Hi sir, what if the ip address starts from 100.20.1.33 …. to …. 100.20.1.48 as the total ip's are 16=2^4… But how will the first IP be evenly divisible by the size of the block?

• No words to appreciate the explanation for power of 2…content from 12.34 😘😘😘👏👏👏👏

• 172.31.4.2/15 is this a valid CIDR block or IP adress are valid

• evenly divisible and divisible is one and the same thing 🙂

• You make my day

• Poorly explained!!!

• He is an amazing teacher. But watching videos of clasfull addressing and then coming to know that 1990 was the year when the tech was last used is horrifying

• What an explanation sir..mind blowing sir..👍🤩👏 👏👏

• Very Nice, you explained it very well, you nailed it.. Thanks.

• Slight silly mistake in 100.1.2.35/28 example, the range will be from 16 – 31. Great lecture btw.

• 91/2k people ,just watch again,u will regret to dislike such a amazing lecture

• superb…I just loved it. Thank you so much

• Excellent instructional ability…

• Since my M.Tech days you are actually my guru. You are teaching a topic by including all possible perspectives and no need to by-heart it.After listening to your lecture,I wonder why these people disliked your video?But your class is superb 👍.Hats off for your service.

• Wonderful video. Thanks a lot for explaining in the simplest form. Keep the good work

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