Computer Networks 21 | Fragmentation in IPv4 | CS & IT | GATE Crash Course

22 thoughts on “Computer Networks 21 | Fragmentation in IPv4 | CS & IT | GATE Crash Course”

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• Can anyone explain Q9 and Q12

• Great lecture sir

• 1:23:47

• Sir in 12th, i guess option B (7, 247) is correct but instead of 247 it should 248 in the answer.

• (at 28.21 time) since 2nd fragment is re-fragmented into 2packets and MF =1 for both. if last fragment (i.e.140|20) was required to re-fragment (let say re-fragmented into 2 packets) then MF will be 0 or 1?

• 13 ka 37 fragments ayega…56*36=2016…2020-2016=4B+40header ka b 37th packet banega ….

• Sir pls solve the homework questions

• Love you sir ♥️

• My favourite teacher ♥️♥️♥️

• Ankit sir is Diamond of PW♥️♥️♥️

• Sir aap questions kl discuss kabhi nhi kerthe

• That question 7 made by you was really good. Couldn't observe that! Really nice

• Hello Sir,

  Kindly find the answer to the HW questions:-

  6. 144
  8. 880
  9. 6

  Kindly check the answers, Sir..!

  The best question in this session I would say was question no 7.

  Thank you, Sir..!

• sir,time mile to bit stuffing bhi pada dena please

• Amazing explanation sir 💖💖💖💖💖

• Thankyou sir. Your every class is extraordinary ❤️❤️❤️

• Ankit sir is Best of Best in computer network….sir aapka crash course itna superb hai…tou fir full course kesa hoga☺️☺️☺️
  Or fir abhyas batch…. humari to parti ho gai…. honestly yesa lagta hai apse computer network padne k bad me forozen ko bhi computer network pada skta hun😂😂😂
  Honestly sir your respect is increasing day by day in my heart….love respect…and salute to you for make everything simple and providing quality content

• I admire what you do. Too many people think that teaching is an easy profession—because teachers make it look easy! Simply tell a teacher that you recognize how hard their job is. That’s likely enough to make them smile

• I Don't have a words to describe your strength in computer network….am completely speechless.
  am telling it because this topic was so complex for many students but you made it so simple
  .
  .
  honestly sir love your class million times thanks to teach us computer network

• H/W ANSWER

  Q6) F.O. VALUE OF 3RD FRAG. = 144
  Q8) T.L. VALUE OF LAST FRAG. = 880
  Q9) NO. OF FRAG. = 6
  Q10) SEQ. NO. OF 1ST BYTE OF PACKET = 800
  Q11) D (DF=1 so, fragmentation is not possible)
  Q12) B
  Q13) TOTAL NO. OF IP FRAG. AFTER FRAGMENTATION = 36

  Sir, 2 hrs ka session hota hai, but time ka pta nahi chalta 🙂🤩😊

• Wonderful sir.I am in 1st year cse but understood every thing till nowin Computer networks.

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