Lec-69: TCP Congestion Control in Computer Networks in Hindi

48 thoughts on “Lec-69: TCP Congestion Control in Computer Networks in Hindi”

• can anyone tell me why only we took 2 as gap after 16 val is it because of the mss value

• Sir you should teach first
  What is congestion control ?

• very well explained sirr.

• make a video on BBR congestion control algorithm , how is works?

• If MSS is 2KB, how come we exponentially grow segment size in slow start phase? 2 to 4 to 8 to 16 when mss is only 2kb?

• this is the aimd protocol right?

• many times MSS refers to maximum segment size. In exam how could I know what they actually mean by MSS in case they don't mention it explicitly?

• Sir is video ko computer networks k playlist me dal dijye taki students easily dundh paye

• 00:01 The question is about TCO congestion protocol.
  01:47 Congestion control in TCP works in three phases.
  03:17 Congestion can be severe or light depending on the number of acknowledgements received.
  04:52 Slow start and exponential growth followed by linear growth in TCP congestion control
  06:32 Congestion is detected due to 3 acknowledgements.
  07:57 Using linear phase to find the threshold value and determining the number of segments to send.
  09:29 TCP congestion control and finding total number of RTTs
  11:08 The answer to the question varies between 1100 to 1300.
  Crafted by Merlin AI.

• Computer networks mcqs sir send me sir

• Sir, in the first case you used TCP tahoe and in 2nd case you used TCP reno. Any specific reason for that?

• sir divide by 2 isliye kiya kyuki mss 2 hai?

• thoda samja bi diya kro sir bina samjaye conjection control numerical bata diya

• it's been 4 years still your playlist is best on youtube!!

• 💕♥️

• 9:57 lekin pehle to apne ghabrana nhi hai 🙃🙃

• Sir what about in university exams? Which answer is correct 1200ms or 1100ms??

• Someone please help , by giving notes link of this subject

• What if MSS IS 1
  THEN WHAT IS THE EXPO OF 1

• Thank you sir ❣️

• hame ghabrana ni h …..10.00

• Love From Pakistan You are a Real GEM💗

• If they mention in question there is no congestion still we need to follow graph like first we have to calculate threshold value that's all ?

• Its a blessing to have teacher like you sir ….nd that too for free …yeah

• you must tell which protocol you are using for congestion control, TCP Tahoe or Reno as they reacts differently for 3ACK case

• Sir, threshold should be 8….
  Sol. = 32kb/2kb /2
  = 16mss/2
  = 8

• Thank you so much

• can someone please explain what is 3 ack received in this case?

• Sir aapko books bhi provide karwani chahiye

• Mic ka aawas kis kis ko sunaai diya

• This video was not very clear. Lot of terms were not explained clearly. Also there are 2 different aspects of TCP: a) Flow Control b) Congestion Control. Difference between them wasn't explained.

• Thank you sir

• U are the very best …Mr sir…👌👌👌

• You teach very well to clear our concepts. But in this video you didn't explain the congestion control and congestion control principles. Student will understand much better if you first explain these things and then move to the questions. Thanks

• Great videos Sir.

• Like: Manchester City FC
  Comment: Juventus FC
  Dislike: Liverpool FC

• Why are we adding 2 in linear phase
  I thought in linear we only increase by 1

• Genuinely, a gr8 teacher hatts off to u sir

• please explain this 3ACK scenario

• Sir, in linear growth phase, are you adding 2 , because MSS = 2KB ?

• Sir aur jo hm add kr rahe hai Linear mai vo everytime 2 add krna hai ya MSS add krna hai

• Sir isme threshold mai divide by 2 krna hai ya divided by MSS krna hai

• Now it clear …Thank you so much

• THANK YOU..

• All hails down!!!

• Hello Sir, i really love your videos for the short and to the point explanation. Here i want to point out to two mistakes in this video.
  1. You are using TCP RENO method for congestion control. If it receives 3 duplicate ACKs then the threshold is half of current value and the transmission starts at threshold+3. You have started it from threshold itself which is not the case.
  2. There are 11 RTTs so the answer should be 1100 not 1200

• Nielit course is available sir..

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